(2x+22)+(3x-2)=90

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Solution for (2x+22)+(3x-2)=90 equation: 



(2x+22)+(3x-2)=90

We move all terms to the left:

(2x+22)+(3x-2)-(90)=0

We get rid of parentheses

2x+3x+22-2-90=0

We add all the numbers together, and all the variables

5x-70=0

We move all terms containing x to the left, all other terms to the right

5x=70

x=70/5

x=14

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