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(2x+22)=(x+17)
We move all terms to the left:
(2x+22)-((x+17))=0
We get rid of parentheses
2x-((x+17))+22=0
We calculate terms in parentheses: -((x+17)), so:We get rid of parentheses
(x+17)
We get rid of parentheses
x+17
Back to the equation:
-(x+17)
2x-x-17+22=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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