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(2x+23)(x+13)=
We move all terms to the left:
(2x+23)(x+13)-()=0
We add all the numbers together, and all the variables
(2x+23)(x+13)=0
We multiply parentheses ..
(+2x^2+26x+23x+299)=0
We get rid of parentheses
2x^2+26x+23x+299=0
We add all the numbers together, and all the variables
2x^2+49x+299=0
a = 2; b = 49; c = +299;
Δ = b2-4ac
Δ = 492-4·2·299
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-3}{2*2}=\frac{-52}{4} =-13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+3}{2*2}=\frac{-46}{4} =-11+1/2 $
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