(2x+24)(2x+18)=660

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Solution for (2x+24)(2x+18)=660 equation:



(2x+24)(2x+18)=660
We move all terms to the left:
(2x+24)(2x+18)-(660)=0
We multiply parentheses ..
(+4x^2+36x+48x+432)-660=0
We get rid of parentheses
4x^2+36x+48x+432-660=0
We add all the numbers together, and all the variables
4x^2+84x-228=0
a = 4; b = 84; c = -228;
Δ = b2-4ac
Δ = 842-4·4·(-228)
Δ = 10704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{10704}=\sqrt{16*669}=\sqrt{16}*\sqrt{669}=4\sqrt{669}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(84)-4\sqrt{669}}{2*4}=\frac{-84-4\sqrt{669}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(84)+4\sqrt{669}}{2*4}=\frac{-84+4\sqrt{669}}{8} $

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