(2x+24)(2x+24)=720

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Solution for (2x+24)(2x+24)=720 equation:



(2x+24)(2x+24)=720
We move all terms to the left:
(2x+24)(2x+24)-(720)=0
We multiply parentheses ..
(+4x^2+48x+48x+576)-720=0
We get rid of parentheses
4x^2+48x+48x+576-720=0
We add all the numbers together, and all the variables
4x^2+96x-144=0
a = 4; b = 96; c = -144;
Δ = b2-4ac
Δ = 962-4·4·(-144)
Δ = 11520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{11520}=\sqrt{2304*5}=\sqrt{2304}*\sqrt{5}=48\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-48\sqrt{5}}{2*4}=\frac{-96-48\sqrt{5}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+48\sqrt{5}}{2*4}=\frac{-96+48\sqrt{5}}{8} $

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