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(2x+25)(2x+16)=580
We move all terms to the left:
(2x+25)(2x+16)-(580)=0
We multiply parentheses ..
(+4x^2+32x+50x+400)-580=0
We get rid of parentheses
4x^2+32x+50x+400-580=0
We add all the numbers together, and all the variables
4x^2+82x-180=0
a = 4; b = 82; c = -180;
Δ = b2-4ac
Δ = 822-4·4·(-180)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-98}{2*4}=\frac{-180}{8} =-22+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+98}{2*4}=\frac{16}{8} =2 $
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