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(2x+26)(5x-7)=180
We move all terms to the left:
(2x+26)(5x-7)-(180)=0
We multiply parentheses ..
(+10x^2-14x+130x-182)-180=0
We get rid of parentheses
10x^2-14x+130x-182-180=0
We add all the numbers together, and all the variables
10x^2+116x-362=0
a = 10; b = 116; c = -362;
Δ = b2-4ac
Δ = 1162-4·10·(-362)
Δ = 27936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{27936}=\sqrt{144*194}=\sqrt{144}*\sqrt{194}=12\sqrt{194}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(116)-12\sqrt{194}}{2*10}=\frac{-116-12\sqrt{194}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(116)+12\sqrt{194}}{2*10}=\frac{-116+12\sqrt{194}}{20} $
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