(2x+27)+(3x-18)=(6x-23)

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Solution for (2x+27)+(3x-18)=(6x-23) equation:



(2x+27)+(3x-18)=(6x-23)
We move all terms to the left:
(2x+27)+(3x-18)-((6x-23))=0
We get rid of parentheses
2x+3x-((6x-23))+27-18=0
We calculate terms in parentheses: -((6x-23)), so:
(6x-23)
We get rid of parentheses
6x-23
Back to the equation:
-(6x-23)
We add all the numbers together, and all the variables
5x-(6x-23)+9=0
We get rid of parentheses
5x-6x+23+9=0
We add all the numbers together, and all the variables
-1x+32=0
We move all terms containing x to the left, all other terms to the right
-x=-32
x=-32/-1
x=+32

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