(2x+28)+(4x+45.5)=90

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Solution for (2x+28)+(4x+45.5)=90 equation: 



(2x+28)+(4x+45.5)=90

We move all terms to the left:

(2x+28)+(4x+45.5)-(90)=0

We get rid of parentheses

2x+4x+28+45.5-90=0

We add all the numbers together, and all the variables

6x-16.5=0

We move all terms containing x to the left, all other terms to the right

6x=16.5

x=16.5/6

x=2+1.8/2.4

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