(2x+28)+(5x+36)=99

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Solution for (2x+28)+(5x+36)=99 equation: 



(2x+28)+(5x+36)=99

We move all terms to the left:

(2x+28)+(5x+36)-(99)=0

We get rid of parentheses

2x+5x+28+36-99=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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