(2x+28)=(4x-2)

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Solution for (2x+28)=(4x-2) equation: 



(2x+28)=(4x-2)

We move all terms to the left:

(2x+28)-((4x-2))=0

We get rid of parentheses

2x-((4x-2))+28=0



We calculate terms in parentheses: -((4x-2)), so:

(4x-2)

We get rid of parentheses

4x-2

Back to the equation:

-(4x-2)



We get rid of parentheses

2x-4x+2+28=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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