(2x+2x)+(x+x)=1200

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Solution for (2x+2x)+(x+x)=1200 equation:



(2x+2x)+(x+x)=1200
We move all terms to the left:
(2x+2x)+(x+x)-(1200)=0
We add all the numbers together, and all the variables
(+4x)+(+2x)-1200=0
We get rid of parentheses
4x+2x-1200=0
We add all the numbers together, and all the variables
6x-1200=0
We move all terms containing x to the left, all other terms to the right
6x=1200
x=1200/6
x=200

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