(2x+3)(2x+2)=4x(-x+5)

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Solution for (2x+3)(2x+2)=4x(-x+5) equation: 



(2x+3)(2x+2)=4x(-x+5)

We move all terms to the left:

(2x+3)(2x+2)-(4x(-x+5))=0

We add all the numbers together, and all the variables

(2x+3)(2x+2)-(4x(-1x+5))=0

We multiply parentheses ..

(+4x^2+4x+6x+6)-(4x(-1x+5))=0



We calculate terms in parentheses: -(4x(-1x+5)), so:

4x(-1x+5)

We multiply parentheses

-4x^2+20x

Back to the equation:

-(-4x^2+20x)



We get rid of parentheses

4x^2+4x^2+4x+6x-20x+6=0

We add all the numbers together, and all the variables

8x^2-10x+6=0

a = 8; b = -10; c = +6;
Δ = b2-4ac
Δ = -102-4·8·6
Δ = -92
Delta is less than zero, so there is no solution for the equation

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