(2x+3)(2x+3)=12x+109

Solution for (2x+3)(2x+3)=12x+109 equation:

Simplifying
(2x + 3)(2x + 3) = 12x + 109

Reorder the terms:
(3 + 2x)(2x + 3) = 12x + 109

Reorder the terms:
(3 + 2x)(3 + 2x) = 12x + 109

Multiply (3 + 2x) * (3 + 2x)
(3(3 + 2x) + 2x * (3 + 2x)) = 12x + 109
((3 * 3 + 2x * 3) + 2x * (3 + 2x)) = 12x + 109
((9 + 6x) + 2x * (3 + 2x)) = 12x + 109
(9 + 6x + (3 * 2x + 2x * 2x)) = 12x + 109
(9 + 6x + (6x + 4x2)) = 12x + 109

Combine like terms: 6x + 6x = 12x
(9 + 12x + 4x2) = 12x + 109

Reorder the terms:
9 + 12x + 4x2 = 109 + 12x

Add '-12x' to each side of the equation.
9 + 12x + -12x + 4x2 = 109 + 12x + -12x

Combine like terms: 12x + -12x = 0
9 + 0 + 4x2 = 109 + 12x + -12x
9 + 4x2 = 109 + 12x + -12x

Combine like terms: 12x + -12x = 0
9 + 4x2 = 109 + 0
9 + 4x2 = 109

Solving
9 + 4x2 = 109

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + 4x2 = 109 + -9

Combine like terms: 9 + -9 = 0
0 + 4x2 = 109 + -9
4x2 = 109 + -9

Combine like terms: 109 + -9 = 100
4x2 = 100

Divide each side by '4'.
x2 = 25

Simplifying
x2 = 25

Take the square root of each side:
x = {-5, 5}