(2x+3)(2x+3)=16x+8

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Solution for (2x+3)(2x+3)=16x+8 equation: 



(2x+3)(2x+3)=16x+8

We move all terms to the left:

(2x+3)(2x+3)-(16x+8)=0

We get rid of parentheses

(2x+3)(2x+3)-16x-8=0

We multiply parentheses ..

(+4x^2+6x+6x+9)-16x-8=0

We get rid of parentheses

4x^2+6x+6x-16x+9-8=0

We add all the numbers together, and all the variables

4x^2-4x+1=0

a = 4; b = -4; c = +1;
Δ = b2-4ac
Δ = -42-4·4·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{4}{8}=1/2$

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