(2x+3)(2x+5)=(2x+3)(2x+5)

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Solution for (2x+3)(2x+5)=(2x+3)(2x+5) equation: 



(2x+3)(2x+5)=(2x+3)(2x+5)

We move all terms to the left:

(2x+3)(2x+5)-((2x+3)(2x+5))=0

We multiply parentheses ..

(+4x^2+10x+6x+15)-((+4x^2+10x+6x+15))=0



We calculate terms in parentheses: -((+4x^2+10x+6x+15)), so:

(+4x^2+10x+6x+15)

We get rid of parentheses

4x^2+10x+6x+15

We add all the numbers together, and all the variables

4x^2+16x+15

Back to the equation:

-(4x^2+16x+15)



We get rid of parentheses

4x^2-4x^2+10x+6x-16x+15-15=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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