(2x+3)(3x+1)=11x+30

Solution for (2x+3)(3x+1)=11x+30 equation:

Simplifying
(2x + 3)(3x + 1) = 11x + 30

Reorder the terms:
(3 + 2x)(3x + 1) = 11x + 30

Reorder the terms:
(3 + 2x)(1 + 3x) = 11x + 30

Multiply (3 + 2x) * (1 + 3x)
(3(1 + 3x) + 2x * (1 + 3x)) = 11x + 30
((1 * 3 + 3x * 3) + 2x * (1 + 3x)) = 11x + 30
((3 + 9x) + 2x * (1 + 3x)) = 11x + 30
(3 + 9x + (1 * 2x + 3x * 2x)) = 11x + 30
(3 + 9x + (2x + 6x2)) = 11x + 30

Combine like terms: 9x + 2x = 11x
(3 + 11x + 6x2) = 11x + 30

Reorder the terms:
3 + 11x + 6x2 = 30 + 11x

Add '-11x' to each side of the equation.
3 + 11x + -11x + 6x2 = 30 + 11x + -11x

Combine like terms: 11x + -11x = 0
3 + 0 + 6x2 = 30 + 11x + -11x
3 + 6x2 = 30 + 11x + -11x

Combine like terms: 11x + -11x = 0
3 + 6x2 = 30 + 0
3 + 6x2 = 30

Solving
3 + 6x2 = 30

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 6x2 = 30 + -3

Combine like terms: 3 + -3 = 0
0 + 6x2 = 30 + -3
6x2 = 30 + -3

Combine like terms: 30 + -3 = 27
6x2 = 27

Divide each side by '6'.
x2 = 4.5

Simplifying
x2 = 4.5

Take the square root of each side:
x = {-2.121320344, 2.121320344}