(2x+3)(3x-1)=2x(3x+1)+5x-3

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Solution for (2x+3)(3x-1)=2x(3x+1)+5x-3 equation: 



(2x+3)(3x-1)=2x(3x+1)+5x-3

We move all terms to the left:

(2x+3)(3x-1)-(2x(3x+1)+5x-3)=0

We multiply parentheses ..

(+6x^2-2x+9x-3)-(2x(3x+1)+5x-3)=0



We calculate terms in parentheses: -(2x(3x+1)+5x-3), so:

2x(3x+1)+5x-3

We add all the numbers together, and all the variables

5x+2x(3x+1)-3

We multiply parentheses

6x^2+5x+2x-3

We add all the numbers together, and all the variables

6x^2+7x-3

Back to the equation:

-(6x^2+7x-3)



We get rid of parentheses

6x^2-6x^2-2x+9x-7x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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