If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(2x+3)(3x-2)=5
We move all terms to the left:
(2x+3)(3x-2)-(5)=0
We multiply parentheses ..
(+6x^2-4x+9x-6)-5=0
We get rid of parentheses
6x^2-4x+9x-6-5=0
We add all the numbers together, and all the variables
6x^2+5x-11=0
a = 6; b = 5; c = -11;
Δ = b2-4ac
Δ = 52-4·6·(-11)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-17}{2*6}=\frac{-22}{12} =-1+5/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+17}{2*6}=\frac{12}{12} =1 $
| x-28=10+12 | | 9u+35=16u-14= | | 4=2^x+4 | | 0.286*x=1 | | 3(m–4)=2m+3 | | 9=3^x+4 | | -1=-5x+4x-7 | | X+3y=20X-4y=-22 | | 4+7n=39 | | 13=0.5p | | X^210×y^2-20y=125 | | 6x^2-77x+240=0 | | -10=-6x+x+10 | | 5-6x-x=5 | | 2(x+5)^2=18 | | 2(x+5)^2-3=15 | | 4x^2+10=334 | | -7n+6n=4(1+3n)+5(-7n+8) | | -49=-7(-1+7m)+7(8m-7) | | -28+5r=-4(5r+2)+5r | | 1+6(1+7n)=-287 | | 2b+28=3(b+7) | | 24a^2+120=164a | | 6x-5=x²+4 | | -6x/5+2x/15=-4 | | 35m^2+54m+7=0 | | 0,5x+3=6 | | 5b^2=-17b-14 | | 5b^2+17b+14=0 | | 2b+28=150 | | 3(n-2)=5-1 | | 3x+12/3=7 |