(2x+3)(3x-5)=(x+7)(6x-1)

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Solution for (2x+3)(3x-5)=(x+7)(6x-1) equation:



(2x+3)(3x-5)=(x+7)(6x-1)
We move all terms to the left:
(2x+3)(3x-5)-((x+7)(6x-1))=0
We multiply parentheses ..
(+6x^2-10x+9x-15)-((x+7)(6x-1))=0
We calculate terms in parentheses: -((x+7)(6x-1)), so:
(x+7)(6x-1)
We multiply parentheses ..
(+6x^2-1x+42x-7)
We get rid of parentheses
6x^2-1x+42x-7
We add all the numbers together, and all the variables
6x^2+41x-7
Back to the equation:
-(6x^2+41x-7)
We get rid of parentheses
6x^2-6x^2-10x+9x-41x-15+7=0
We add all the numbers together, and all the variables
-42x-8=0
We move all terms containing x to the left, all other terms to the right
-42x=8
x=8/-42
x=-4/21

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