(2x+3)(3x-7)=(2x-3)(3x-4)

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Solution for (2x+3)(3x-7)=(2x-3)(3x-4) equation: 



(2x+3)(3x-7)=(2x-3)(3x-4)

We move all terms to the left:

(2x+3)(3x-7)-((2x-3)(3x-4))=0

We multiply parentheses ..

(+6x^2-14x+9x-21)-((2x-3)(3x-4))=0



We calculate terms in parentheses: -((2x-3)(3x-4)), so:

(2x-3)(3x-4)

We multiply parentheses ..

(+6x^2-8x-9x+12)

We get rid of parentheses

6x^2-8x-9x+12

We add all the numbers together, and all the variables

6x^2-17x+12

Back to the equation:

-(6x^2-17x+12)



We get rid of parentheses

6x^2-6x^2-14x+9x+17x-21-12=0

We add all the numbers together, and all the variables

12x-33=0

We move all terms containing x to the left, all other terms to the right

12x=33

x=33/12

x=2+3/4

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