(2x+3)(5x+2)=5(2x-3)(x-8)

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Solution for (2x+3)(5x+2)=5(2x-3)(x-8) equation: 



(2x+3)(5x+2)=5(2x-3)(x-8)

We move all terms to the left:

(2x+3)(5x+2)-(5(2x-3)(x-8))=0

We multiply parentheses ..

(+10x^2+4x+15x+6)-(5(2x-3)(x-8))=0



We calculate terms in parentheses: -(5(2x-3)(x-8)), so:

5(2x-3)(x-8)

We multiply parentheses ..

5(+2x^2-16x-3x+24)

We multiply parentheses

10x^2-80x-15x+120

We add all the numbers together, and all the variables

10x^2-95x+120

Back to the equation:

-(10x^2-95x+120)



We get rid of parentheses

10x^2-10x^2+4x+15x+95x+6-120=0

We add all the numbers together, and all the variables

114x-114=0

We move all terms containing x to the left, all other terms to the right

114x=114

x=114/114

x=1

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