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(2x+3)(5x+5)=0
We multiply parentheses ..
(+10x^2+10x+15x+15)=0
We get rid of parentheses
10x^2+10x+15x+15=0
We add all the numbers together, and all the variables
10x^2+25x+15=0
a = 10; b = 25; c = +15;
Δ = b2-4ac
Δ = 252-4·10·15
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-5}{2*10}=\frac{-30}{20} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+5}{2*10}=\frac{-20}{20} =-1 $
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