(2x+3)(x)=280

Solution for (2x+3)(x)=280 equation:

(2x+3)(x)=280

We move all terms to the left:

(2x+3)(x)-(280)=0

We multiply parentheses

2x^2+3x-280=0

a = 2; b = 3; c = -280;
Δ = b2-4ac
Δ = 32-4·2·(-280)
Δ = 2249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{2249}}{2*2}=\frac{-3-\sqrt{2249}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{2249}}{2*2}=\frac{-3+\sqrt{2249}}{4}
$