(2x+3)(x)=5000

Solution for (2x+3)(x)=5000 equation:

(2x+3)(x)=5000

We move all terms to the left:

(2x+3)(x)-(5000)=0

We multiply parentheses

2x^2+3x-5000=0

a = 2; b = 3; c = -5000;
Δ = b2-4ac
Δ = 32-4·2·(-5000)
Δ = 40009
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{40009}}{2*2}=\frac{-3-\sqrt{40009}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{40009}}{2*2}=\frac{-3+\sqrt{40009}}{4}
$