(2x+3)(x-2)+(x-2)(x-3)=3x(X-3)

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Solution for (2x+3)(x-2)+(x-2)(x-3)=3x(X-3) equation:



(2x+3)(x-2)+(x-2)(x-3)=3x(x-3)
We move all terms to the left:
(2x+3)(x-2)+(x-2)(x-3)-(3x(x-3))=0
We multiply parentheses ..
(+2x^2-4x+3x-6)+(x-2)(x-3)-(3x(x-3))=0
We calculate terms in parentheses: -(3x(x-3)), so:
3x(x-3)
We multiply parentheses
3x^2-9x
Back to the equation:
-(3x^2-9x)
We get rid of parentheses
2x^2-3x^2-4x+3x+(x-2)(x-3)+9x-6=0
We multiply parentheses ..
2x^2-3x^2+(+x^2-3x-2x+6)-4x+3x+9x-6=0
We add all the numbers together, and all the variables
-1x^2+(+x^2-3x-2x+6)+8x-6=0
We get rid of parentheses
-1x^2+x^2-3x-2x+8x+6-6=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0

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