(2x+3)(x-2)+(x-2)(x-3)=3x(X-3)

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Solution for (2x+3)(x-2)+(x-2)(x-3)=3x(X-3) equation: 



(2x+3)(x-2)+(x-2)(x-3)=3x(x-3)

We move all terms to the left:

(2x+3)(x-2)+(x-2)(x-3)-(3x(x-3))=0

We multiply parentheses ..

(+2x^2-4x+3x-6)+(x-2)(x-3)-(3x(x-3))=0



We calculate terms in parentheses: -(3x(x-3)), so:

3x(x-3)

We multiply parentheses

3x^2-9x

Back to the equation:

-(3x^2-9x)



We get rid of parentheses

2x^2-3x^2-4x+3x+(x-2)(x-3)+9x-6=0

We multiply parentheses ..

2x^2-3x^2+(+x^2-3x-2x+6)-4x+3x+9x-6=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-3x-2x+6)+8x-6=0

We get rid of parentheses

-1x^2+x^2-3x-2x+8x+6-6=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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