(2x+3)(x-7)=(2x+8)(x)

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Solution for (2x+3)(x-7)=(2x+8)(x) equation: 



(2x+3)(x-7)=(2x+8)(x)

We move all terms to the left:

(2x+3)(x-7)-((2x+8)(x))=0

We multiply parentheses ..

(+2x^2-14x+3x-21)-((2x+8)x)=0



We calculate terms in parentheses: -((2x+8)x), so:

(2x+8)x

We multiply parentheses

2x^2+8x

Back to the equation:

-(2x^2+8x)



We get rid of parentheses

2x^2-2x^2-14x+3x-8x-21=0

We add all the numbers together, and all the variables

-19x-21=0

We move all terms containing x to the left, all other terms to the right

-19x=21

x=21/-19

x=-1+2/19

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