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(2x+3)+(2x+2)+(2x)=(2x)+(2x)+(3x+2)
We move all terms to the left:
(2x+3)+(2x+2)+(2x)-((2x)+(2x)+(3x+2))=0
We add all the numbers together, and all the variables
2x+(2x+3)+(2x+2)-(2x+2x+(3x+2))=0
We get rid of parentheses
2x+2x+2x-(2x+2x+(3x+2))+3+2=0
We calculate terms in parentheses: -(2x+2x+(3x+2)), so:We add all the numbers together, and all the variables
2x+2x+(3x+2)
We add all the numbers together, and all the variables
4x+(3x+2)
We get rid of parentheses
4x+3x+2
We add all the numbers together, and all the variables
7x+2
Back to the equation:
-(7x+2)
6x-(7x+2)+5=0
We get rid of parentheses
6x-7x-2+5=0
We add all the numbers together, and all the variables
-1x+3=0
We move all terms containing x to the left, all other terms to the right
-x=-3
x=-3/-1
x=+3
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