(2x+3)+(2x+3)+(x)+(x)=36

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Solution for (2x+3)+(2x+3)+(x)+(x)=36 equation: 



(2x+3)+(2x+3)+(x)+(x)=36

We move all terms to the left:

(2x+3)+(2x+3)+(x)+(x)-(36)=0

We add all the numbers together, and all the variables

2x+(2x+3)+(2x+3)-36=0

We get rid of parentheses

2x+2x+2x+3+3-36=0

We add all the numbers together, and all the variables

6x-30=0

We move all terms containing x to the left, all other terms to the right

6x=30

x=30/6

x=5

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