(2x+3)+(2x+3)+(x+1)+x+1)=26

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Solution for (2x+3)+(2x+3)+(x+1)+x+1)=26 equation: 



(2x+3)+(2x+3)+(x+1)+x+1)=26

We move all terms to the left:

(2x+3)+(2x+3)+(x+1)+x+1)-(26)=0

We add all the numbers together, and all the variables

x+(2x+3)+(2x+3)+(x+1)=0

We get rid of parentheses

x+2x+2x+x+3+3+1=0

We add all the numbers together, and all the variables

6x+7=0

We move all terms containing x to the left, all other terms to the right

6x=-7

x=-7/6

x=-1+1/6

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