(2x+3)+(3x-10)+(x+1)=180

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Solution for (2x+3)+(3x-10)+(x+1)=180 equation: 



(2x+3)+(3x-10)+(x+1)=180

We move all terms to the left:

(2x+3)+(3x-10)+(x+1)-(180)=0

We get rid of parentheses

2x+3x+x+3-10+1-180=0

We add all the numbers together, and all the variables

6x-186=0

We move all terms containing x to the left, all other terms to the right

6x=186

x=186/6

x=31

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