(2x+3)+(3x-2)=21

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Solution for (2x+3)+(3x-2)=21 equation: 



(2x+3)+(3x-2)=21

We move all terms to the left:

(2x+3)+(3x-2)-(21)=0

We get rid of parentheses

2x+3x+3-2-21=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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