(2x+3)+(5x+10)=48

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Solution for (2x+3)+(5x+10)=48 equation: 



(2x+3)+(5x+10)=48

We move all terms to the left:

(2x+3)+(5x+10)-(48)=0

We get rid of parentheses

2x+5x+3+10-48=0

We add all the numbers together, and all the variables

7x-35=0

We move all terms containing x to the left, all other terms to the right

7x=35

x=35/7

x=5

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