(2x+3)+(5x+10)=48

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Solution for (2x+3)+(5x+10)=48 equation:



(2x+3)+(5x+10)=48
We move all terms to the left:
(2x+3)+(5x+10)-(48)=0
We get rid of parentheses
2x+5x+3+10-48=0
We add all the numbers together, and all the variables
7x-35=0
We move all terms containing x to the left, all other terms to the right
7x=35
x=35/7
x=5

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