(2x+3)+(6x-4)=(9x-3)+(8x-16

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Solution for (2x+3)+(6x-4)=(9x-3)+(8x-16 equation: 



(2x+3)+(6x-4)=(9x-3)+(8x-16

We move all terms to the left:

(2x+3)+(6x-4)-((9x-3)+(8x-16)=0

We get rid of parentheses

2x+6x-((9x-3)+(8x-16)+3-4=0

We add all the numbers together, and all the variables

8x-((9x-3)+(8x-16)+3-4=0

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