(2x+3)+(6x-4)=(9x-3)+(8x-16)

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Solution for (2x+3)+(6x-4)=(9x-3)+(8x-16) equation: 



(2x+3)+(6x-4)=(9x-3)+(8x-16)

We move all terms to the left:

(2x+3)+(6x-4)-((9x-3)+(8x-16))=0

We get rid of parentheses

2x+6x-((9x-3)+(8x-16))+3-4=0



We calculate terms in parentheses: -((9x-3)+(8x-16)), so:

(9x-3)+(8x-16)

We get rid of parentheses

9x+8x-3-16

We add all the numbers together, and all the variables

17x-19

Back to the equation:

-(17x-19)



We add all the numbers together, and all the variables

8x-(17x-19)-1=0

We get rid of parentheses

8x-17x+19-1=0

We add all the numbers together, and all the variables

-9x+18=0

We move all terms containing x to the left, all other terms to the right

-9x=-18

x=-18/-9

x=+2

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