(2x+3)+(x+1)=2

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Solution for (2x+3)+(x+1)=2 equation:


Simplifying
(2x + 3) + (x + 1) = 2

Reorder the terms:
(3 + 2x) + (x + 1) = 2

Remove parenthesis around (3 + 2x)
3 + 2x + (x + 1) = 2

Reorder the terms:
3 + 2x + (1 + x) = 2

Remove parenthesis around (1 + x)
3 + 2x + 1 + x = 2

Reorder the terms:
3 + 1 + 2x + x = 2

Combine like terms: 3 + 1 = 4
4 + 2x + x = 2

Combine like terms: 2x + x = 3x
4 + 3x = 2

Solving
4 + 3x = 2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3x = 2 + -4

Combine like terms: 4 + -4 = 0
0 + 3x = 2 + -4
3x = 2 + -4

Combine like terms: 2 + -4 = -2
3x = -2

Divide each side by '3'.
x = -0.6666666667

Simplifying
x = -0.6666666667

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