(2x+3)-(4x-5)=(6x+4)+(8x-7)

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Solution for (2x+3)-(4x-5)=(6x+4)+(8x-7) equation: 



(2x+3)-(4x-5)=(6x+4)+(8x-7)

We move all terms to the left:

(2x+3)-(4x-5)-((6x+4)+(8x-7))=0

We get rid of parentheses

2x-4x-((6x+4)+(8x-7))+3+5=0



We calculate terms in parentheses: -((6x+4)+(8x-7)), so:

(6x+4)+(8x-7)

We get rid of parentheses

6x+8x+4-7

We add all the numbers together, and all the variables

14x-3

Back to the equation:

-(14x-3)



We add all the numbers together, and all the variables

-2x-(14x-3)+8=0

We get rid of parentheses

-2x-14x+3+8=0

We add all the numbers together, and all the variables

-16x+11=0

We move all terms containing x to the left, all other terms to the right

-16x=-11

x=-11/-16

x=11/16

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