(2x+3)/2=(x-1)/5

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Solution for (2x+3)/2=(x-1)/5 equation: 



(2x+3)/2=(x-1)/5

We move all terms to the left:

(2x+3)/2-((x-1)/5)=0

We calculate fractions


2x/()+(-((x-1)*2)/()=0



We calculate terms in parentheses: +(-((x-1)*2)/(), so:

-((x-1)*2)/(

We multiply all the terms by the denominator


-((x-1)*2)



We calculate terms in parentheses: -((x-1)*2), so:

(x-1)*2

We multiply parentheses

2x-2

Back to the equation:

-(2x-2)



We get rid of parentheses

-2x+2

Back to the equation:

+(-2x+2)



We get rid of parentheses

2x/()-2x+2=0

We multiply all the terms by the denominator


2x-2x*()+2*()=0

We add all the numbers together, and all the variables

2x-2x*()=0

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