(2x+3)/3=(3x-15)/11

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Solution for (2x+3)/3=(3x-15)/11 equation: 



(2x+3)/3=(3x-15)/11

We move all terms to the left:

(2x+3)/3-((3x-15)/11)=0

We calculate fractions


2x/()+(-((3x-15)*3)/()=0



We calculate terms in parentheses: +(-((3x-15)*3)/(), so:

-((3x-15)*3)/(

We multiply all the terms by the denominator


-((3x-15)*3)



We calculate terms in parentheses: -((3x-15)*3), so:

(3x-15)*3

We multiply parentheses

9x-45

Back to the equation:

-(9x-45)



We get rid of parentheses

-9x+45

Back to the equation:

+(-9x+45)



We get rid of parentheses

2x/()-9x+45=0

We multiply all the terms by the denominator


2x-9x*()+45*()=0

We add all the numbers together, and all the variables

2x-9x*()=0

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