(2x+3)/3=(3x-2)/5

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Solution for (2x+3)/3=(3x-2)/5 equation: 


x in (-oo:+oo)

(2*x+3)/3 = (3*x-2)/5 // - (3*x-2)/5

(2*x+3)/3-((3*x-2)/5) = 0

(2*x+3)/3+(-1*(3*x-2))/5 = 0

(5*(2*x+3))/(3*5)+(-1*3*(3*x-2))/(3*5) = 0

5*(2*x+3)-1*3*(3*x-2) = 0

x+21 = 0

(x+21)/(3*5) = 0

(x+21)/(3*5) = 0 // * 3*5

x+21 = 0

x+21 = 0 // - 21

x = -21

x = -21

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