(2x+3)/4=(5x-2)/3

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Solution for (2x+3)/4=(5x-2)/3 equation: 



(2x+3)/4=(5x-2)/3

We move all terms to the left:

(2x+3)/4-((5x-2)/3)=0

We calculate fractions


2x/()+(-((5x-2)*4)/()=0



We calculate terms in parentheses: +(-((5x-2)*4)/(), so:

-((5x-2)*4)/(

We multiply all the terms by the denominator


-((5x-2)*4)



We calculate terms in parentheses: -((5x-2)*4), so:

(5x-2)*4

We multiply parentheses

20x-8

Back to the equation:

-(20x-8)



We get rid of parentheses

-20x+8

Back to the equation:

+(-20x+8)



We get rid of parentheses

2x/()-20x+8=0

We multiply all the terms by the denominator


2x-20x*()+8*()=0

We add all the numbers together, and all the variables

2x-20x*()=0

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