(2x+3)/5=(-3x+1)/7

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Solution for (2x+3)/5=(-3x+1)/7 equation: 


x in (-oo:+oo)

(2*x+3)/5 = (1-3*x)/7 // - (1-3*x)/7

(2*x+3)/5-((1-3*x)/7) = 0

(2*x+3)/5+(-1*(1-3*x))/7 = 0

(7*(2*x+3))/(5*7)+(-1*5*(1-3*x))/(5*7) = 0

7*(2*x+3)-1*5*(1-3*x) = 0

29*x+16 = 0

(29*x+16)/(5*7) = 0

(29*x+16)/(5*7) = 0 // * 5*7

29*x+16 = 0

29*x+16 = 0 // - 16

29*x = -16 // : 29

x = -16/29

x = -16/29

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