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(2x+3)/5=7
We move all terms to the left:
(2x+3)/5-(7)=0
We multiply all the terms by the denominator
(2x+3)-7*5=0
We add all the numbers together, and all the variables
(2x+3)-35=0
We get rid of parentheses
2x+3-35=0
We add all the numbers together, and all the variables
2x-32=0
We move all terms containing x to the left, all other terms to the right
2x=32
x=32/2
x=16
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