(2x+3)/5=7

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Solution for (2x+3)/5=7 equation: 



(2x+3)/5=7

We move all terms to the left:

(2x+3)/5-(7)=0

We multiply all the terms by the denominator


(2x+3)-7*5=0

We add all the numbers together, and all the variables

(2x+3)-35=0

We get rid of parentheses

2x+3-35=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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