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(2x+3)/6-(x-1)/3=(x+2)/3+2
We move all terms to the left:
(2x+3)/6-(x-1)/3-((x+2)/3+2)=0
We calculate fractions
((2x+3)*3*3)/()+(-6x+6)/()+(-((x+2)*6)/()=0
We calculate terms in parentheses: +((2x+3)*3*3)/(), so:
(2x+3)*3*3)/(
We multiply all the terms by the denominator
(2x+3)*3*3)
We get rid of parentheses
2x+3)*3*3
We add all the numbers together, and all the variables
2x
Back to the equation:
+(2x)
We calculate terms in parentheses: +(-((x+2)*6)/(), so:We get rid of parentheses
-((x+2)*6)/(
We multiply all the terms by the denominator
-((x+2)*6)
We calculate terms in parentheses: -((x+2)*6), so:We get rid of parentheses
(x+2)*6
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
-6x-12
Back to the equation:
+(-6x-12)
2x+(-6x+6)/()-6x-12=0
We multiply all the terms by the denominator
2x*()+(-6x+6)-6x*()-12*()=0
We add all the numbers together, and all the variables
2x*()+(-6x+6)-6x*()=0
We get rid of parentheses
2x*()-6x-6x*()+6=0
We add all the numbers together, and all the variables
-6x+2x*()-6x*()+6=0
We move all terms containing x to the left, all other terms to the right
-6x+2x*()-6x*()=-6
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