(2x+3)/7=(x-9)/4

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Solution for (2x+3)/7=(x-9)/4 equation: 



(2x+3)/7=(x-9)/4

We move all terms to the left:

(2x+3)/7-((x-9)/4)=0

We calculate fractions


2x/()+(-((x-9)*7)/()=0



We calculate terms in parentheses: +(-((x-9)*7)/(), so:

-((x-9)*7)/(

We multiply all the terms by the denominator


-((x-9)*7)



We calculate terms in parentheses: -((x-9)*7), so:

(x-9)*7

We multiply parentheses

7x-63

Back to the equation:

-(7x-63)



We get rid of parentheses

-7x+63

Back to the equation:

+(-7x+63)



We get rid of parentheses

2x/()-7x+63=0

We multiply all the terms by the denominator


2x-7x*()+63*()=0

We add all the numbers together, and all the variables

2x-7x*()=0

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