(2x+3)/7=6

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Solution for (2x+3)/7=6 equation: 



(2x+3)/7=6

We move all terms to the left:

(2x+3)/7-(6)=0

We multiply all the terms by the denominator


(2x+3)-6*7=0

We add all the numbers together, and all the variables

(2x+3)-42=0

We get rid of parentheses

2x+3-42=0

We add all the numbers together, and all the variables

2x-39=0

We move all terms containing x to the left, all other terms to the right

2x=39

x=39/2

x=19+1/2

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