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(2x+3)20=15(8)
We move all terms to the left:
(2x+3)20-(15(8))=0
determiningTheFunctionDomain (2x+3)20-158=0
We multiply parentheses
40x+60-158=0
We add all the numbers together, and all the variables
40x-98=0
We move all terms containing x to the left, all other terms to the right
40x=98
x=98/40
x=2+9/20
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