(2x+3)2=64

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Solution for (2x+3)2=64 equation: 



(2x+3)2=64

We move all terms to the left:

(2x+3)2-(64)=0

We multiply parentheses

4x+6-64=0

We add all the numbers together, and all the variables

4x-58=0

We move all terms containing x to the left, all other terms to the right

4x=58

x=58/4

x=14+1/2

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