(2x+3)2=64

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Solution for (2x+3)2=64 equation:



(2x+3)2=64
We move all terms to the left:
(2x+3)2-(64)=0
We multiply parentheses
4x+6-64=0
We add all the numbers together, and all the variables
4x-58=0
We move all terms containing x to the left, all other terms to the right
4x=58
x=58/4
x=14+1/2

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