(2x+3)6x-5)=0

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Solution for (2x+3)6x-5)=0 equation:



(2x+3)6x-5)=0
We add all the numbers together, and all the variables
(2x+3)6x=0
We multiply parentheses
12x^2+18x=0
a = 12; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·12·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*12}=\frac{-36}{24} =-1+1/2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*12}=\frac{0}{24} =0 $

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