(2x+3)=(20)+(x+10)

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Solution for (2x+3)=(20)+(x+10) equation: 



(2x+3)=(20)+(x+10)

We move all terms to the left:

(2x+3)-((20)+(x+10))=0

We get rid of parentheses

2x-(20+(x+10))+3=0



We calculate terms in parentheses: -(20+(x+10)), so:

20+(x+10)

determiningTheFunctionDomain
(x+10)+20

We get rid of parentheses

x+10+20

We add all the numbers together, and all the variables

x+30

Back to the equation:

-(x+30)



We get rid of parentheses

2x-x-30+3=0

We add all the numbers together, and all the variables

x-27=0

We move all terms containing x to the left, all other terms to the right

x=27

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